RESUMEN
Ten diterpene quinones, which inhibited the binding of [3H]flunitrazepam to central benzodiazepine receptors with IC50s ranging from 0.3 to 36.2 microM, were isolated from the ethereal extract of the roots of Salvia miltiorrhiza. Among these natural products, miltirone has the highest potency (IC50 = 0.3 microM). It was orally active in an animal model used to predict clinical tranquilizing effects. Unlike diazepam, miltirone behaved as a partial agonist in the central benzodiazepine receptor binding and behavioural tests. Moreover, it produced no acute muscle relaxant effect and did not induce drug dependence and withdrawal reactions after chronic administration in mice.
Asunto(s)
Fenantrenos/metabolismo , Receptores de GABA-A/metabolismo , Abietanos , Diazepam/farmacología , Medicamentos Herbarios Chinos , Fenantrenos/química , Fenantrenos/farmacología , Plantas Medicinales , Receptores de GABA-A/efectos de los fármacos , Ácido gamma-Aminobutírico/metabolismoRESUMEN
Twenty one o-quinonoid-type compounds and one coumarin-type compound related to miltirone (1) have been synthesized with the aim to identify the key structural elements involved in miltirone's interaction with the central benzodiazepine receptor. On the basis of their inhibition of [3H]flunitrazepam binding to bovine cerebral cortex membranes, it is apparent that ring A of miltirone is essential for affinity. Although increasing the size of ring A from six-membered to seven- and eight-membered is well-tolerated, the introduction of polar hydroxyl groups greatly reduces binding affinity. The presence of 1,1-dimethyl groups on ring A is, however, not essential. On the other hand, the isopropyl group on ring C appears to be critical for binding as its removal decreases affinity by more than 30-fold. It can, however, be replaced with a methyl group with minimal reduction in affinity. Finally, linking ring A and B with a -CH2CH2- bridge results in analogue 89, which is 6 times more potent than miltirone at the central benzodiazepine receptor (IC50 = 0.05 microM).