Your browser doesn't support javascript.
loading
Show: 20 | 50 | 100
Results 1 - 3 de 3
Filter
Add more filters











Database
Language
Publication year range
1.
Chemosphere ; 182: 738-744, 2017 Sep.
Article in English | MEDLINE | ID: mdl-28531840

ABSTRACT

The Fenton process, one of several advanced oxidation processes, describes the reaction of Fe(II) with hydrogen peroxide. Fe(II) is oxidized to Fe(III) that reacts with hydrogen peroxide to Fe(II) and again initiates the Fenton reaction. In the course of the reactions reactive species, e.g. hydroxyl radicals, are formed. Conditions such as pH, ligand concentrations and the hydrogen peroxide/Fe(II) ratio may influence the OH radical yield. It could be shown that at pH < 2.7 and >3.5 the OH radical yield decreases significantly. Two ligands were investigated, pyrophosphate and sulfate. It was found that pyrophosphate forms a complex with Fe(III) that does not react with hydrogen peroxide and thus, the Fenton reaction is terminated and the OH radical yields do not further increase. The influence of sulfate is not as strong as that of pyrophosphate. The OH radical yield is decreased when sulfate is added but even at higher concentrations the Fenton reaction is not terminated.


Subject(s)
Diphosphates/chemistry , Ferrous Compounds/chemistry , Hydrogen Peroxide/chemistry , Hydroxyl Radical/chemical synthesis , Iron/chemistry , Sulfates/chemistry , Hydrogen-Ion Concentration , Ligands , Oxidation-Reduction
2.
Environ Sci Technol ; 49(19): 11714-20, 2015 Oct 06.
Article in English | MEDLINE | ID: mdl-26371826

ABSTRACT

Ozone is often used in the treatment of drinking water. This may cause problems if the water to be treated contains bromide as its reaction with ozone leads to the formation of bromate, which is considered to be carcinogenic. Bromate formation is a multistep process resulting from the reaction of ozone with bromite. Although this process seemed to be established, it has been shown that ozone reacts with bromite not by the previously assumed mechanism via O transfer but via electron transfer. Besides bromate, the electron-transfer reaction also yields O3(•-), the precursor of OH radicals. The experiments were set up in such a way that OH radicals are not produced from ozone self-decomposition but solely by the electron-transfer reaction. This study shows that hydroxyl radicals are indeed generated by using tBuOH as the OH radical scavenger and measuring its product, formaldehyde. HOBr and bromate yields were measured in systems with and without tBuOH. As OH radicals contribute to bromate formation, higher bromate and HOBr yields were observed in the absence of tBuOH than in its presence, where all OH radicals are scavenged. On the basis of the results presented here, a pathway from bromide to bromate, revised in the last step, was suggested.


Subject(s)
Bromates/chemistry , Bromides/chemistry , Ozone/chemistry , Formaldehyde/chemistry , Hydrogen-Ion Concentration , Hydroxyl Radical/chemistry , Methanol/chemistry , Phenols/chemistry
3.
Environ Sci Technol ; 47(17): 9959-64, 2013 Sep 03.
Article in English | MEDLINE | ID: mdl-23883394

ABSTRACT

The peroxone process is one of the AOPs that lead to (•)OH. Hitherto, it has been generally assumed that the (•)OH yield is unity with respect to O3 consumption. Here, experimental data are presented that suggest that it must be near 0.5. The first evidence is derived from competition experiments. The consumption of 4-chlorobenzoic acid (4-CBA), 4-nitrobenzoic acid (4-NBA) and atrazine present in trace amounts (1 µM) has been followed as a function of the O3 concentration in a solution containing H2O2 (1 mM) and tertiary butanol (tBuOH, 0.5 mM) in excess over the trace compounds. With authentic (•)OH generated by γ-radiolysis such a competition can be adequately fitted by known (•)OH rate constants. Fitting the peroxone data, however, the consumption of the trace indicators can only be rationalized if the (•)OH yield is near 0.5 (4-CBA: 0.56, 4-NBA: 0.49, atrazine: 0.6). Additional information for an (•)OH yield much below unity has been obtained by a product analysis of the reactions of tBuOH with (•)OH and dimethyl sulfoxide with (•)OH. The mechanistic interpretation for the low (•)OH yield is as follows (Merényi et al. Environ. Sci. Technol. 2010, 44, 3505-3507). In the reaction of O3 with HO2(-) an adduct (HO5(-)) is formed that decomposes into O3(•-) and HO2(•) in competition with 2 O2 + OH(-). The latter process reduces the free-radical yield.


Subject(s)
Atrazine/chemistry , Chlorobenzoates/chemistry , Environmental Pollutants/chemistry , Nitrobenzoates/chemistry , Hydrogen Peroxide/chemistry , Hydroxyl Radical/chemistry , Oxidation-Reduction , Ozone/chemistry
SELECTION OF CITATIONS
SEARCH DETAIL